Question

solve: x+3 by 2= 9x - 5 by 5​

Answer 1

Answer:

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Answer 2

Answer:

Answer: The equation can be factorized as: x3 – 3x2 – 9x – 5 = (x+1)2 (x+5)

We will find one of the zeros of the expression x3 – 3x2 – 9x – 5 and use long division to find the other zeros.

Explanation:

Substitute 5 for x in x3 – 3x2 – 9x – 5

53 – 3(5)2 – 9(5) – 5 = 125 - 75 - 45 - 5 = 0

So, 5 is a zero of the expression x3 – 3x2 – 9x – 5

This means (x - 5) is a factor of x3 – 3x2 – 9x – 5

Divide x3 – 3x2 – 9x – 5 by x - 5

factorization of x3 – 3x2 – 9x – 5

This means x3 – 3x2 – 9x – 5 = (x - 5) (x2 + 2x + 1) = (x - 5) (x+1)2

Therefore, the factorization of x3 – 3x2 – 9x – 5 is (x - 5) (x+1)2

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