Math, asked by sahotajassi307, 5 hours ago

solve (x+3) (x-2)=0

Answers

Answered by Jha28utkarsh
1

Answer:

x = -2 or x = 3

Step-by-step explanation:

=> (x+3) (x-2) = 0

=> x(x-2) + 3(x-2) = 0

=>x^{2} -2x+3x-6

=> x^{2} +x-6 =0

Using the equation x = (-b±(√b²-4ac))/2a

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

=> x^{2} + x -6 = 0

a = 1

b = 1

c = -6

Substituting the values,

x = (-1±(√1²-4×1×-6))/2×1

On evaluating, we get,

x = (-1±5)/2

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

=>x = \frac{-1+5}{2}  = 2

=> x = \frac{-1-5}{2} = -3

Answered by baldevsingh558833
0

Answer:

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