Question

solve x-3/x+4<0 and draw graph​

Answer 1

Answer:

(- 4, 3)

Step-by-step explanation:

$\frac{x-3}{x+4}$ < 0 (x = - 4)

There are two critical point (-4) and 3 which divide an x-axis into three intervals: (- ∞, - 4), (- 4, 3) and (3, ∞) . Let analyze sign of function f(x) = $\frac{x-3}{x+4}$

on each of those intervals.

Let pick

x = - 10, f(- 10) = $\frac{-10-3}{-10+4}$ = $\frac{13}{6}$ > 0

x = 0, f(0) = - $\frac{3}{4}$ < 0

x = 10, f(10) = $\frac{10-3}{10+4}$ = $\frac{1}{2}$ > 0

⇒ the solution is interval (- 4, 3)