Math, asked by kongnovchit26, 2 months ago

solve (x-3)(x²-2x+4)=2

Answers

Answered by sehgalp381
18

Answer:

(x - 3)(x {}^{2}  - 2x +  4) = 2 \\x  {}^{3}  -2 x {}^{2}  + 4x - 3x {}^{2}  + 6x - 12 \\ x {}^{3}   - 5x { }^{2}  + 10 - 12 \\ x {}^{3}  - 5x {}^{2}  - 2

Step-by-step explanation:

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Answered by LoverBoy346
0

{x}^{3}    -  {x}^{2}   + 2x + 10 = 0

Step-by-step explanation:

 {(x -3)}( {x}^{2}  - 2x - 4) = 2

 {x}^{3}  - 2 {x}^{2}  - 4x - 3 {x}^{2}  + 6x + 12 = 2

 {x}^{3}  -  {x}^{2}    + 2x + 12 = 2

{x}^{3}    -  {x}^{2}   + 2x + 10 = 0

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