Question

solve: x/3 +y/5 =2 ; x/3+y/2=1​

Answer 1

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let , the equations i and ii.

On solving the equations

we get ,

$5x + 3y = 30 \: \: \: \: - iii \\ 2x + 3y = 6 \: \: \: \: \: - iv \\ now. \\ eqn \: iii - eqn \: iv$

$we \: get \: . \\ 3x = 24 \\ x = \frac{24}{3} \\ = > x = 8 \\ now \: put \: the \: value \: of \: x \: in \: eqn .\: iv \\ 2x + 3y = 6 \\ 2 \times 8 + 3y = 6 \\ 16 + 3y = 6 \\ 3y = 6 - 16 \\ 3y = - 10 \\ y = \frac{ - 10}{3}$

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