Solve:
X-3y-3=0
3x-9y-2=0
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a1 x + b1 y − c1 = 0 a2 x + b2 y − c2 = 0 Here, a1 = 1, b1 = −3, c1 = −3 a2 = 3, b2 = −9, c2 = −2 So according to the question, we get a1a2a1a2 = 1313 b1b2b1b2 = −3−9−3−9 = 1313 and, c1c2c1c2 = −3−2−3−2 = 3232 ⇒ a1a2a1a2 =b1b2b1b2 ≠ c1c2c1c2
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