Question

solve x^4 +2x^3-5x^2+6x+2 given that 1+I is a root​

Answer 1

Answer:

5x 2−6x−2=0

D=b 2 −4ac=36−4(5)(−2)=76

x= 2a−b± D

= 10−(−6)± 76

= 106± 76

= 53± 19

5x −6x−2=5( 53+ 19) 2−6( 53+ 19)−2

= 59+19+6

19 − 5

(18+6 19 )−2 =2−2=0

similarly ( 53− 19 ) also can be checked

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