Solve: x^4 – 2x^3 – x^2 – 2x + 1 = 0 and please don't scam.
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Answer:
[(3±√5)/2] ;
[(-1±√3i)/2]
Step-by-step explanation:
given equation :
let's take '' common from above equation
⇒
it is converted as :
⇒
rearrange the above equation;
⇒
let = A ;
squaring on both sides , we get ;
= A²;
substitute value of A and A² in above equation
A² - 2 - 2A - 1 =0 ; A² - 2A -3 =0
A² - 3A + A -3 =0;
(A-3)(A+1) =0
so A can be 3 or (-1)
so can be 3 or (-1)
let = 3;
[(3±√5)/2]
if we consider = -1;
[(-1±√3i)/2]
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