Question

Solve (x-4)/7 -(x+4)/5 = (x+3)/7.​

Answer 1

Answer:

Solution :-

✪ $\dfrac{(x - 4)}{7} - \dfrac{(x + 4)}{5} = \dfrac{(x + 3)}{7}$

$\implies \dfrac{(x - 4)}{7} - \dfrac{(x + 4)}{5} - \dfrac{(x + 3)}{7} = 0$

$\implies \dfrac{5x - 20 - 7x - 28 - 5x - 15}{35} = 0$

$\implies \dfrac{5x - 7x - 5x - 20 - 28 - 15}{35} = 0$

$\implies \dfrac{- 7x - 63}{35} = 0$

$\implies \dfrac{- 7(x + 9)}{35} = 0$

$\implies \dfrac{- (x + 9)}{5} = 0$

$\therefore\sf\: The\: answer\: of\: this\: question\: is\: \dfrac{- (x + 9)}{5}$

Answer 2

Answer: The answer is 9.

Step-by-step explanation:

Given that,

(x-4)/7 -(x+4)/5 = (x+3)/7

=> {5(x - 4) - 7(x + 4)} / 35 = (x + 3)/7

=> (5x - 20 - 7x - 28)/35 = (x+3)/7

=>(-2x - 48)/35 = (x +3)/7

=> -14x - 336 = 35x + 105

=> 49x = 441

=> x = 441/49 = 9