Question

Solve x.
4(x+3) = 18

Answer 1

• As per the data given in the question, we have to find the value of $x.$

       Given data:- $4(x+3)=18.$

       To find:- value of the $x$.

       Solution:-

• Here, we will use the below following steps to find a solution using the transposition method:
• Step 1:- we will Identify the variables and constants in the given simple equation.

• Step 2:-Then we Simplify the equation in LHS and RHS.

• Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.

• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.

• Step 5:- Then the result will be the solution for the given linear equation.

        By using the transposition method. we get,

        Therefore,

          $\Rightarrow 4(x+3)=18\\\Rightarrow 4x+12=18\\\Rightarrow 4x=18-12\\\Rightarrow 4x=6\\\Rightarrow x=\frac{6}{4}=\frac{3}{2}.$

        Hence, the value of $x$ will be $\frac{3}{2}.$

Answer 2

Given that:- $4(x+3) = 18$

As we have to find the value of 'x',

For that, we have to use the BODMAS rule

Solve the left side term by distributing,

$=>4x+4\times3 = 18$

$=>4x+12=18$

Subtract both sides by $12$ ,

$=>4x+12-12=18-12$

By simplifying it we get,

$=>4x=18-12$

$=>4x=6$

Now, divide by 4 into both sides,

$=>\frac{4x}{4}=\frac{6}{4}$

$=>x=\frac{6}{4}$

For the numerator and the denominator, we have to find the GCF (greatest common factor)

$=>x=\frac{3\times 2}{2\times 2}$

Factor out and then cancel the GCF,

$=>x=\frac{3}{2}$

Hence, the value of the x is $\frac{3}{2}.$