solve: (x-5)^2+(x-4)^3+(x-3)^4 = 0
Answers
Answered by
6
Answer:
x−2
+
x−5
x−4
=
3
10
⇒
(x−3)(x−5)
(x−2)(x−5)+(x−3)(x−4)
=
3
10
⇒
x
2
−8x+15
x
2
−7x+10+x
2
−7x+12
=
3
10
⇒
x
2
−8x+15
2x
2
−14x+22
=
3
10
⇒3(2x
2
−14x+22)=10(x
2
−8x+15)
⇒6x
2
−42x+66=10x
2
−80x+150
⇒10x
2
−80x+150−6x
2
+42x−66=0
⇒4x
2
−38x+84=0
⇒2x
2
−19x+42=0
⇒x=
2×2
19±
19
2
−4×2×42
⇒x=
4
19±
25
⇒x=
4
19±5
⇒x=
4
19+5
,
4
19−5
∴x=
4
24
,
4
14
∴x=6,
2
7
Step-by-step explanation:
Answered by
1
Answer:
Step-by-step explanation:
(x−3)
4
+(x−4)
3
+(x−5)
2
EXPAND
x
4
−11x
3
+43x
2
−70x+42
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