Math, asked by swetanks2007, 3 months ago

solve: (x-5)^2+(x-4)^3+(x-3)^4 = 0​

Answers

Answered by Aditikumari100
6

Answer:

x−2

+  

x−5

x−4

=  

3

10

 

⇒  

(x−3)(x−5)

(x−2)(x−5)+(x−3)(x−4)

=  

3

10

 

⇒  

x  

2

−8x+15

x  

2

−7x+10+x  

2

−7x+12

=  

3

10

 

⇒  

x  

2

−8x+15

2x  

2

−14x+22

=  

3

10

 

⇒3(2x  

2

−14x+22)=10(x  

2

−8x+15)

⇒6x  

2

−42x+66=10x  

2

−80x+150

⇒10x  

2

−80x+150−6x  

2

+42x−66=0

⇒4x  

2

−38x+84=0

⇒2x  

2

−19x+42=0

⇒x=  

2×2

19±  

19  

2

−4×2×42

 

 

⇒x=  

4

19±  

25

 

 

⇒x=  

4

19±5

 

⇒x=  

4

19+5

,  

4

19−5

 

∴x=  

4

24

,  

4

14

 

∴x=6,  

2

7

Step-by-step explanation:

Answered by Santhiyasenthilkumar
1

Answer:

Step-by-step explanation:

(x−3)  

4

+(x−4)  

3

+(x−5)  

2

 

EXPAND

x  

4

−11x  

3

+43x  

2

−70x+42

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