solve x÷5+3x÷2+5x÷3??
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Given as x/5 < (3x - 2)/4 – (5x - 3)/5 x/5 < [5(3x - 2) – 4(5x - 3)]/4(5) x/5 < [15x – 10 – 20x + 12]/20 x/5 < [2 – 5x]/20 Multiplying both the sides by 20 we get, x/5 × 20 < [2 – 5x]/20 × 20 4x < 2 – 5x 4x + 5x < 2 – 5x + 5x 9x < 2 Dividing both sides by 9, we get 9x/9 < 2/9 x < 2/9 Therefore, the solution of the given inequation is (-∞, 2/9).Read more on Sarthaks.com - https://www.sarthaks.com/799390/solve-the-linear-inequations-in-r-x-5-3x-2-4-5x-3-5
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