Math, asked by batitakadyan, 3 months ago

solve x^5 - 4x^3 + x^3 + 3x + 1 ÷ x^3 - 3x + 1​

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Answered by smile1234op
1

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Answered by OoINTROVERToO
1

DIVIDEND = x⁵ - 4x³ + x³ + 3x + 1

DIVISOR = x³ - 3x + 1

\begin{gathered} {x}^{3} - 3x + 1) {x}^{5} - 4 {x}^{3} + {x}^{2} + 3x + 1( {x}^{2} - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {x}^{2} - 3 {x}^{3} + {x}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = = = = = = = = = = = \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - {x}^{3} + 3x + 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - {x}^{3} + 3x - 1\: \: \: \: \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = = = = = = = = = = = = \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2\end{gathered}

REMAINDER = 2

QUOTIENT = (x² - 1)

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