solve x^5+4x^4+x^3+x^2+4x+1=0
Answers
Answered by
16
Solution
The solution is x= -1
substitute x=-1 in the below equation
x^5+4x^4+x^3+x^2+4x+1
(-1)^5 +4(-1)^4+(-1)^3 +(-1)^2 + 4(-1) +1
(-1)+ (4) + (-1) + (1) + (-4) +1
-1+4-1+1-4+1
=0
Hence x = -1
The solution is x= -1
substitute x=-1 in the below equation
x^5+4x^4+x^3+x^2+4x+1
(-1)^5 +4(-1)^4+(-1)^3 +(-1)^2 + 4(-1) +1
(-1)+ (4) + (-1) + (1) + (-4) +1
-1+4-1+1-4+1
=0
Hence x = -1
Answered by
14
Step-by-step explanation:
The solution is x= -1
substitute x=-1 in the below equation x^5+4x^4+x^3+x^2+4x+1
(-1)^5 +4(-1)^4+(-1)^3 +(-1)^2 + 4(-1) +1
(-1)+ (4) + (-1) + (1) + (-4) +1
-1+4-1+1-4+1
=0
Hence x = -1
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