Question

Solve: (x-5)(x+5)+25

Answer 1

(x - 5)(x + 5) + 25 = 0
$x^{2}$ - 25 + 25 = 0 
$x^{2}$ = 0
x = 0

Answer 2

= [x+(-5)] (x+5) + 25 = 0
= (-5+x) (5+x) + 25 = 0
= (-5 + x) (5 + x)
= [-5(5 + x) + x(5 + x)] + 25 = 0
= [{5 × -5 + x × (-5) }+ x(5 + x)] + 25 = 0
= [(-25 + -5x) + x(5 + x)] + 25 = 0
= [-25 + -5x + (5 * x + x * x)] + 25 = 0
= [-25 + -5x + (5x + x2)] + 25 = 0
= -5x + 5x = 0
= (-25 + 0 + x2) + 25 = 0
= (-25 + x2) + 25 = 0
= -25 + 25 + x2 = 0
= -25 + 25 = 0
= 0 + x2 = 0 x2 = 0
= x2 = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Simplifying x2 = 0
Take the square root of each side: x = {0}