Math, asked by hackersharmabest, 7 months ago

solve X + 6 upon X + 5 - 2 x minus one upon x minus 4 + X + 4 upon x minus 2 is equal to zero​
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Answers

Answered by vivekshah91
0

Step-by-step explanation:

(x+6/x+5-2x) -(4+x+4/x-2)=0

(x+6/5-x) - (x+8/x-2)=0

(x+6)(x-2) – (5-x)(x+8) = (5-x)(x-2)

(x²+6x-2x-12)–(5x-x²+40-8x) = 5x-10-x²+2x

x²+6x-2x-12-5x+x²-40+8x=7x-x²-10

2x²+7x-52=7x-x²-10

2x²+7x-7x+x²=52-10

3x²=42

x²=14

x=√14

x=2√3

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