Solve : ( x-6)(x+7)=(x+3)(x-11) with explanation pls...
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Let's solve your equation step-by-step.
(x−6)(x+7)=(x+3)(x−11)
Step 1: Simplify both sides of the equation.
x^2+x−42=x^2−8x−33
Step 2: Subtract x^2 from both sides.
x^2+x−42−x^2=x^2−8x−33−x^2
x−42=−8x−33
Step 3: Add 8x to both sides.
x−42+8x=−8x−33+8x
9x−42=−33
Step 4: Add 42 to both sides.
9x−42+42=−33+42
9x=9
Step 5: Divide both sides by 9.
9x9=9/9
x=1
(x−6)(x+7)=(x+3)(x−11)
Step 1: Simplify both sides of the equation.
x^2+x−42=x^2−8x−33
Step 2: Subtract x^2 from both sides.
x^2+x−42−x^2=x^2−8x−33−x^2
x−42=−8x−33
Step 3: Add 8x to both sides.
x−42+8x=−8x−33+8x
9x−42=−33
Step 4: Add 42 to both sides.
9x−42+42=−33+42
9x=9
Step 5: Divide both sides by 9.
9x9=9/9
x=1
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