solve
x-a/x-b+x-b/x-a=a²+b²/ab
( no unnecessary answers )
Answers
Answered by
1
Answer:
Step-by-step explanation:
x-a/x-b + x-b/x-a = a² + b²/ab
=> (x-a)² + (x-b)² / (x-a)(x-b) = a² + b²/ab
=> x² - 2ax + a² + x² - 2bx + b² / x² - x(a+b) + ab = a² + b²/ab
=> 2x² - 2x(a+b) + a² + b² / x² - x(a+b) + ab = a² + b²/ab
=> ab(2x² - 2x(a+b) + a² + b²) = (a² + b²) (x² - x(a+b) + ab)
=> 2abx² - 2ab(a+b)x + ab(a²+b²) = x²(a² + b²) - (a+b)(a²+b²)x + ab(a²+b²)
=> - 2ab(a+b)x + (a+b)(a²+b²)x = x²(a² + b² -2ab) (∵ab(a²+b²) is striked out)
=> (a+b)x( a²+b² -2ab) = x²(a² + b² -2ab)
=> x(a+b)(a-b)² = x²(a-b)² (∵ (a-b)² is striked out)
=> x² -x(a+b) = 0
=> x(x - (a+b)) = 0
=> x = 0 or x - (a+b) = 0
=> x = 0 or x = a+b
Answered by
0
x = 0 or (a+b)
Similar questions
Social Sciences,
2 months ago
English,
2 months ago
Social Sciences,
6 months ago
Math,
6 months ago
Math,
11 months ago