Question

Solve x and y: 2(3x-y)=5xy and 2(x+y)=5xy

Answer 1

Step-by-step explanation:

$\Huge\red{\mathfrak{ Answer }}$

2(3x-y) = 5xy

=> 6x-2y= 5xy

=> 6x-5xy= 2y

=> x(6-5y)= 2y

=> x= 2y/6-5y

Putting x= 2y/6-5y in 2(x+y)= 5xy we have

2( 2y/6-5y+y)= 5(2y/6-5y)y

=> 2( 2y+6y-5y^2/6-5y)= 5( 2y^2/6-5y)

=> 16y-10y^2/6-5y= 10y^2/6-5y

=> 16y-10y^= 10y^2

=> 16y-20y^2= 0

=> 4y(4-5y)= 0

=> 4-5y= 0

=> -5y = -4

=>y= -4/-5

=>y = 4/5

x = 2y/6-5y= 2(4/5)/ 6-5(4/5)

= (8/5)/ 6-4

=(8/5)/ 2

= 8/5* 1/2

= 4/5

so x= 4/5

y= 4/5

hope it helps ✌