Question

solve x and y :- 2/x+y + 3/x-y=1 , 8/x+y - 7/x-y = 5/6​

Answer 1

Answer:

x=4;y=0

Step-by-step explanation:

I hope so it will help u

Answer 2

Answer:

$\frac{2}{x + y} + \frac{3}{x - y} = 1 \\ \frac{8}{x + y} - \frac{7}{x - y} = \frac{5}{6} \\ \\ Let, \: \: \frac{1}{x + y} \: \: be \: \: u \: \: and \: \: \frac{1}{x - y} \: \: be \: \: v \\ \\ 2u + 3v = 1 \: \: \: \: \: \: (1) \\ 8u - 7v = \frac{5}{6} \: \: \: \: \: (2) \\ \\ 2u + 3v = 1 \\ 2u = 1 - 3v \\ u = \frac{1 - 3v}{2} \\ \\ 8u - 7v = \frac{5}{6} \\ 8( \frac{1 - 3v}{2} ) - 7v = \frac{5}{6} \\ \frac{8 - 24v}{2} - 7v = \frac{5}{6} \\ \frac{8 - 24v - 14v}{2} = \frac{5}{6} \\ \frac{8 - 38v}{2} = \frac{5}{6} \\ 6(8 - 38v) = 2 \times 5 \\ 48 - 228v = 10 \\ 48 - 10 = 228v \\ \frac{38}{228} = v \\ \boxed{ \underline {\underline{ \frac{1}{6}}} = v }\\ \\ 2u + 3v = 1 \\ 2u + 3( \frac{1}{6} ) = 1 \\ 2u + \frac{1}{2} = 1 \\ 2u = 1 - \frac{1}{2} \\ 2u = \frac{2 - 1}{2} \\ u = \frac{1}{2} \div 2 \\ u = \frac{1}{2} \times \frac{1}{2} \\ \boxed{u = \underline {\underline{ \frac{1}{4} }}} \\ \\ \frac{1}{x + y} = u \\ \frac{1}{x + y} = \frac{1}{4} \\ \boxed{ \boxed{4 = x + y}} \\ \\ \frac{1}{x - y} = v \\ \frac{1}{x - y} = \frac{1}{6} \\ \boxed{ \boxed{6 = x - y}} \\ 6 + y = x \\ \\ x + y = 4 \\ (6 + y) + y = 4 \\ 6 + y + y = 4 \\ 6 + 2y = 4 \\ 2y = 4 - 6 \\ y = \frac{ - 2}{2} \\ \boxed{ \boxed{y = \underline{ \underline{- 1}}}} \\ \\ x - y = 6 \\ x - ( - 1) = 6 \\ x + 1 = 6 \\ x = 6 - 1 \\ \boxed{ \boxed{x = \underline{ \underline{5}}}}$

Step-by-step explanation:

x = 5

y = -1