Math, asked by meena6979, 10 months ago

Solve x and y. 5/x+6y=13. 3/x+4y=7. Y not equal to 0

Answers

Answered by tube666
0

Step-by-step explanation:

The given equations are:

(i)5/x + 6y = 13

(ii)3/x + 4y = 7

Putting 1/x = u we get

(iii)5u + 6y = 13

(iv)3u + 4y = 7

On multiplying (iii) by 4 and (iv) by 6, we get

(v)20u + 24y = 52

(vi)18u + 24y = 42

On subtracting (vi) from (v) we get

2u = 10 => u = 5

=> 1/x = 5

=> x =1/5

On substituting x = 1/5 in (i) we get

5/1/3 / + 6y = 13

25 + 6y = 13

6y = (13 - 25) = -12

y = -2

Hence

x = 1/5

y = -2

Similar questions