solve x and y in substitution method(i) 2x-3y=13
7x-2y=20
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Hey!!
2x - 3y = 13-------(1)
7x - 2y = 20--------(2)
From eq'n (1)
2x - 3y = 13
=> 2x = 13 + 3y
=> x = 13 + 3y / 2------(3)
Substitute eq'n (3) in eq'n (2)
7x - 2y = 20
=> 7 ( 13 + 3y / 2 ) - 2y = 20
=> 91 + 21y - 4y = 40
=> 17y = 40 - 91
=> 17y = - 51
=> y = - 51 / 17
=> y = - 3 >>>>> Answer
From eq'n (3)
x = 13 + 3y / 2
=> x = 13 + 3 ( - 3 ) / 2
=> x = 13 - 9 / 2
=> x = 4 / 2
=> x = 2 >>>>>> Answer
Therefore the value of x = 2 and y = - 3
___________________________
Hope it will helps you✌✌
2x - 3y = 13-------(1)
7x - 2y = 20--------(2)
From eq'n (1)
2x - 3y = 13
=> 2x = 13 + 3y
=> x = 13 + 3y / 2------(3)
Substitute eq'n (3) in eq'n (2)
7x - 2y = 20
=> 7 ( 13 + 3y / 2 ) - 2y = 20
=> 91 + 21y - 4y = 40
=> 17y = 40 - 91
=> 17y = - 51
=> y = - 51 / 17
=> y = - 3 >>>>> Answer
From eq'n (3)
x = 13 + 3y / 2
=> x = 13 + 3 ( - 3 ) / 2
=> x = 13 - 9 / 2
=> x = 4 / 2
=> x = 2 >>>>>> Answer
Therefore the value of x = 2 and y = - 3
___________________________
Hope it will helps you✌✌
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