Question

Solve x and y , log x base y +log y base x =8÷3

Answer 1

let log x base y=x ..so we have logy basex=1/x

so we have quadratic equation3x^2+3-8x=0

so we have x={8+√(64-36)}/6

x=8+2√7 and 8-√7

solve for x=logx base y you get answer

but I think the question should be

logxbasey-logybasex=8÷3

so you can get logx base y=3 or logx base y=-1/3

solve for x and y

you get x=y^3

Answer 2

Answer:

Are there any conditions or soo?

Step-by-step explanation