solve:- x+b/a-b = x-b/a+b
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Step-by-step explanation:
Given: x-a/b +x-b/a = b/x-a + a/x-b
a(x-a)+b(x-b)/ab = b(x-b) + a(x-a)/(x-a)(x-b)
Here Numerator on both sides are Equal so They Cancel Out, We Get
1/ab = 1/(x-a)(x-b)
(x-a)(x-b) = ab
x2-(a+b)x + ab = ab
x{x-(a+b)} = 0
Therefore X=0 or X-(a+b) = 0
X= 0 or (a+b)
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