Solve
x-b-c/a + x-c-a/b + x-a-b/c = 3
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Answer:
(x-b-c)/a+(x-a-b)/c+(x-c-a)/b=3
Bc(x-b-c)+ab(x-a-b)+ac(x-c-a)=3abc
Bcx-b²c-bc² +abx- a²b -ab² +acx -a²c -ac²=3 abc
Abx+bcx +cax=3 abc+ a²b +ab²+ b²c+ bc²+ a²c+ ac²
X(ab+bc+ac)= abc+ a²b +ab²+ abc+ b²c +bc²+ abc +a²c +ac²
X(ab+bc+ac)=ab(c+a+b)+bc(a+b+c)+ac(b+a+c)
X(ab+bc+ac) =(a+b+c) (ab +bc+ ac)
X =(a+b+c) (ab+bc+ac)/(ab+bc+ac)
X=a+b+c
Hope this one is the correct ans.. !!
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