Question

Solve x: in the following problem:

Answer 1

Answer:

${3}^{2} ( {7}^{0} + {4}^{3x} ) = 9 \frac{9}{16} \\ 9(1 + {4}^{3x} ) = \frac{153}{16} \\ 1 + {4}^{3x} = \frac{17}{16} \\ {4}^{3x} = \frac{17}{16} - 1 \\ {4}^{3x} = \frac{1}{16} = {16}^{ - 1} \\ {4}^{3x} = {4}^{ - 2} \\ 3x = - 2 \\ x = \frac{ - 2}{3}$

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