Question

solve 'x' in the given pair of equations using substitution method. 2x+y=3 and x+3y=1

Answer 1

Heya!!

The euations are :

2x + y = 3 .........(i)

x + 3y = 1 ...........( ii )


In eq (ii)

x + 3y = 1

=) x = 1 - 3y ...........(iii)


Now,


In eq (i)

2x + y = 3

=) 2 ( 1 - 3y ) + y = 3

=) 2 - 6y + y = 3

=) 2 - 5y = 3

=) 5y = -1

=) y = -1 / 5


________________________


Then,


In eq (iii)

x = 1 - 3y

=) x = 1 - 3 ( -1/5 )

=) x = 1 + 3/5

=) x = ( 5 + 3 ) / 5

=) x = 8/5


Hence, the value of x = 8/5 and y = -1/5 .


Hope it helps uh :)