solve x square -2x+3=0 by using quadratic
formula
Answers
Answered by
0
Answer:
given below
Step-by-step explanation:
we have 4x
2
+4
3x
+3=0
Here, a=4,b=4
3
and c=3
Therefore, D=b
2
−4ac=(4
3
)
2
−4×4×3=48−48=0
∴ D=0 roots exist and are equal
Thus, x=
2a
−b±
D
=
2×4
−4
3
±
0
=
2
−3
Hence the roots of given equation are
2
−3
and
2
−3
Similar questions