solve X square + 4 x minus- 12 by factorization
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x^2+4x-12
x^2-2x+6x-12
x(x-2)+6(x--2)
x=2
x=-6
Answered by
7
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Answer:
p(x)=x²+4x-12=0(let); if x is a zero of
Step-by-step explanation:
x²+6x-2x-12=0
x(x+6)-2(x+6)=0
(x-2)(x+6)=0
either, x-2=0 or x+6=0
x=2 or x=–6
Therefore, the value of x in given polynomial is either '2' or '-6'
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