Question

solve x square - 8 x + 16 is equals to zero​

Answer 1

Answer:

x^2-8x+16=0

by factorication methood

(x-4)(x-4)=0

Answer 2

Answer :

The value of x is either 4 or 4

Given :

The quadratic equation is

• $\sf {x}^{2} - 8x + 16 = 0$

To Find :

• The value of x

Solution :

Splitting the middle term of the given polynomial :

$\sf {x}^{2} - 8x + 16 = 0 \\ \implies \sf {x}^{2} - 4x - 4x + 16 = 0 \\ \sf \implies x(x - 4) - 4(x - 4) = 0 \\ \sf \implies(x - 4)(x - 4) = 0$

Thus the roots of the equation are :

$\sf x - 4 = 0 \: \: and \: \: x - 4 = 0 \\ \sf \implies x = 4 \: and \: \implies x = 4$

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Alternative method for factorisation (applying formula ) :

• (a - b)² = a² - 2ab + b²

$\sf {x}^{2} - 8x + 16 = 0 \\ \implies \sf {x}^{2} - 2 \times 4 \times x + ( {4)}^{2} = 0 \\ \implies \sf{(x - 4)}^{2} = 0 \\ \implies \sf(x - 4)(x - 4) = 0$

Thus the roots are :

$\sf{x - 4 = 0} \: and \: \: x - 4 = 0 \\ \sf\implies x = 4 \: \:and \: \implies x = 4$