solve x to the power 9+y to the power 9
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USING ALGEBRAIC IDENTITY :-
=> (a³+b³) = [(a+b)(a²-ab+b²)]
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=> (x³)³ + (y³)³
=> [x³+y³].[(x³)²-x³y³+(y³)²]
=> [(x+y)(x²-xy+y²)][(x²)³+(y²)³-x³y³]
=> [(x+y)(x²-xy+y²)].[{(x²+y²)((x²)²+(y²)²-x²y²)} - x³y³]
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Deepsbhargav:
sorry...phle kuch mistake ho gai thi
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