Solve x (x-1)dy/dx-(x-2)y=x3(2x-1)
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The differential equation x (x-1)dy/dx-(x-2)y = x³(2x-1) can be solved in the following ways:
- As per the question,
x (x-1)dy/dx - (x-2)y = x³(2x-1)
- Dividing both sides by x(x-1), we get,
dy / dx - (x-2) / x(x-1) = x²(2x-1) / (x-1)
- Let, a = , where P = -(x-2) / x(x-1)
- Now, Solving :
= - ∫ [(x-1) + (-1)] / x(x-11)
= ∫ - 1/ x + ∫ 1 / (x² - x)
= - ln x + ln (x-1) / x
= ln (x-1)/x²
- Therefore we get =
= (x-1)/x²
- Now, y * a = x²(2x-1) / (x-1) * a
y * (x-1)/x² = ∫ x²(2x-1) / (x-1) * (x-1)/x²
= x² - x + C
- Therefore, y = x² / (x-1) * ( x² - x + C )
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