Solve x/x+15=4/9 please answer
Answers
Answer:
Step-by-step explanation:
S O L U T I O N :
\underline{\bf{Given\::}}
Given:
The perimeter of a rhombus is 60 cm. If the length of its longer diagonal measures 24 cm.
\underline{\bf{Explanation\::}}
Explanation:
As we know that formula of the perimeter of rhombus;
\boxed{\bf{Perimeter = 4 \times side}}
Perimeter=4×side
A/q
\mapsto\tt{Perimeter\:of\:rhombus = 4 \times side}↦Perimeterofrhombus=4×side
\mapsto\tt{60 = 4 \times side}↦60=4×side
\mapsto\tt{Side = \cancel{60/4}}↦Side=
60/4
\mapsto\tt{Side = 15\:cm}↦Side=15cm
Therefore,the all side of rhombus will be 15 cm .
Now, attachment a figure, a/c question:
In ΔOCB :
AC = 24 cm
OC = 1/2 AC
OC = 1/2 × 24
OC = 12 cm
Using by Pythagoras Theorem :
→ (Hypotenuse)² = (Base)² + (perpendicular)²
→ (BC)² = (OC)² + (OB)²
→ (15)² = (12)² + (OB)²
→ 225 = 144 + 0B²
→ OB² = 225 - 144
→ OB² = 81
→ OB = √81
→ OB = 9 cm
&
BD = 2 × OB
BD = 2 × 9
BD = 18 cm
Thus,
The shorter diagonal will be 18 cm
Cancel terms that are in both the numerator and denominator
/ + 1 5 = 4/9
1/ 1 + 1 5 = 4 /9 Result
1 /6 = 4 /9