Solve: x(x+2)(x^2-1)=-1
Answers
Answered by
0
Answer:
The answer is (x^2 + 2x)(x^2 - 1) = -1
x^4 - x^2 + 2x^3 - 2x = p(x)
(-1)^4 - (-1)^2 + 2(-1)^3 - 2(-1) =p(-1)
1 - 1 - 2 + 2 = 0
0 = 0
p(-1) = 0
HENCE SOLVED
Step-by-step explanation:
Answered by
0
Answer:
x=−1.618034,0.618034
Step-by-step explanation:
Let's solve your equation step-by-step.
x(x+2)(x2−1)=−1
x4+2x3−x2−2x=−1
Step 1: Subtract -1 from both sides.
x4+2x3−x2−2x−(−1)=−1−(−1)
x4+2x3−x2−2x+1=0
Step 2: Use quartic formula.
x=−1.618034,0.618034
Similar questions