Question

solve x(x+2)(x^2-1) = -1​

Answer 1

Step-by-step explanation:

Given x

2 +x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

$x=2a−b±b2−4ac</p><p></p><p></p><p>$

$</p><p>2(1)−1±12−4{(a+2)(a+1)}</p><p></p><p></p><p>$

−1±

1−4{−(a

2

+3a+2)

x=

2

−1±

1+4a

2

+12a+8

=

2

−1±

4a

2

+12a+9

=

2

−1±

(2a+3)

2

=

2

−1±(2a+3)

∴x=

2

−1+2a+3

and x=

2

−1−2a−3

∴x=

2

2a+2

and x=

2

−2a−4

x=a+1x=−(a+2)

∴ The roots of x

2

+x−(a+2)(a+1)=0 are (a+1) and −(a+2)