Question

solve x=√(x+20) for all x∈r​

Answer 1

Answer:

$x = \sqrt{x + 20} \\ {x}^{2} = x + 20 \\ {x}^{2} - x - 20 = 0 \\ {x}^{2} - 5x + 4x - 20 = 0 \\ x(x - 5) + 4(x - 5) = 0 \\ (x - 5)(x + 4) = 0 \\ x = 5 \: and \: x \: = - 4 \\ as \:square \: root \: can \: never \: be \: negative \\ so \: x \: = 5$

Answer 2

Answer:

this is correct..........................