Solve x-y=1 and 2x-3y=5 by elimination method
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Answered by
0
here is your answer by Sujeet yaduvanshi,
x-y=1
2x-3y=5
solving the equation by elimination method,
x-y=1. *2
2x-3y=5. *1
2x-2y=2
2x-3y=5
________
y=3
then,
putting the value of y in another equation,,
x-y=1
x-3=1
x=1+3
x=4
that's all
x-y=1
2x-3y=5
solving the equation by elimination method,
x-y=1. *2
2x-3y=5. *1
2x-2y=2
2x-3y=5
________
y=3
then,
putting the value of y in another equation,,
x-y=1
x-3=1
x=1+3
x=4
that's all
Answered by
2
by elimination method
x- y=1............i)
2x-3y=5........ii)
now multiply 2 in i) eq and 1 in ii) eq.
x-y=1. ×2
2x-3y=5. ×1
2x-2y=2. iii)
2x-3y=5. iv)
now,
subtract iii) from iv)
2x-2y=2
2x-3y=5
- + -
_______
0+y=-3
______
so y=-3
put this value in i) eq
x-y=1
x-(-3)=1
x+3=1
x=1-3
x=-2
thetefore,
x=-2 , y=-3
justification,,,
x-y=1
-2-(-3)=1
-2+3=1
1=1
it is clear that our ans is right
hope it helps u....
x- y=1............i)
2x-3y=5........ii)
now multiply 2 in i) eq and 1 in ii) eq.
x-y=1. ×2
2x-3y=5. ×1
2x-2y=2. iii)
2x-3y=5. iv)
now,
subtract iii) from iv)
2x-2y=2
2x-3y=5
- + -
_______
0+y=-3
______
so y=-3
put this value in i) eq
x-y=1
x-(-3)=1
x+3=1
x=1-3
x=-2
thetefore,
x=-2 , y=-3
justification,,,
x-y=1
-2-(-3)=1
-2+3=1
1=1
it is clear that our ans is right
hope it helps u....
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