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(x+y+1)dx + (x+y+2)dy =0
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Step-by-step explanation:
dx ( x+y+1) + (x+y+2) dy =0
dx ( x + y +1) + dy (x+y+2 ) = 0
d [ x(x+y+1) + y(x+y+2 ) =0
divide both side by x
d=0
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