solve x+y=12 x(x) +y(y) =78
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Question : The sum of the ages of a boy and his elder brother is 12 years and the sum of the squares of their ages is 74 (in year. Find their ages.
Step-by-step explanation :
Let the ages of the boy be x years and that of his elder brother be y years, y > x.
ATQ,
x + y = 12 ..... (1)
x^2 + y^2 = 74 ..... (2)
Squaring both sides of (1), we get
(x + y)^2 = 12^2
or, x^2 + y^2 + 2xy = 144
or, 74 + 2xy = 144
or, 2xy = 70
Now, (x - y)^2 = x^2 + y^2 - 2xy
= 74 - 70
= 4
i.e., y - x = 2 ..... (3), since y > x
Adding (1) and (2), we get
x + y + y - x = 12 + 2
or, 2y = 14
or, y = 7
Putting y = 7 in (1), we get
x + 7 = 12
or, x = 12 - 7
or, x = 5
Therefore age of the boy is 5 years and that of his elder brother is 7 years.
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