Solve x+y=14 and x-y=4 and hence find the value of 'm' for which y=mx+3
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Given equations are
2x+3y=11−−−−(1)
2x−4y=−24−−−−(2)
Form (1)
2x+3y=11
⇒2x=11−3y
⇒x=
2
11−3y
−−−(3)
substituting x in(2)
2x−4y=−24
⇒2(
2
11−3y
)−4y=−24
⇒11−3y−4y=−24
⇒11−7y=−24
⇒7y=35
⇒y=35/7
⇒y=5.
putting y = 5 in (3)
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