Math, asked by Karthik2580, 1 year ago

solve x + y = 18,y + 2 =12,2 + x = 16

Answers

Answered by sadafparveen711
0

Let x+y=18---(1), y+z=12---(2),z+x=16---(3) Solving (2)-(3) we get y+z-z-x=12-16 y-x=-4--(4) Solving (4)+(5) we get x+y+y-x=18-4 2y=14 y=14/2=7 Substitute y value in (1) x+7=18 x=18-7=11 Substitute x value in (3) z+11=16 z=16-11=5 x=11, y=7, z=5

Answered by Anonymous
0

Answer:

x+y=18---(1),

y+z=12---(2)

,z+x=16---(3)

Solving (2)-(3) we get

y+z-z-x=12-16

y-x=-4--(4)

Solving (4)+(5) we get

x+y+y-x=18-4

2y=14 y=14/2=7

Substitute y value in (1)

x+7=18 x=18-7=11

Substitute x value in (3)

z+11=16 z=16-11=5

x=11, y=7, z=5

Answer is this only lvs

Similar questions