Solve : x-y =2 ; x+y=4
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➺ x-y =2 ; x+y=4
⟹ x-y =2
⟹ x =2+y
Substituting value of x in x+y=4
⟹x+y= 4
⟹(2+y)+y= 4
⟹2+2y= 4
⟹2y= 4–2
⟹2y= 2
⟹[y= 1]
Now, again substituting value of y in x-y=2
⟹x-y = 2
⟹x-1 = 2
⟹x = 2+1
⟹[x = 3]
∴x= 3 and y=1
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Answer:
x-y=2----1
x+y=4----2
substrate eq.2to1
x+y=4---2
x-y=2----1
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2x=6
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therefore x=6/2=3 therefore x=3
substitute x=3in eq.2
x+y=4
3+y=4
y=4-3
y=1
(x,y)=(3,1)
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