Math, asked by gireeshnaidu04, 11 months ago

solve x+y-2z+3w=0 x-2y+z-w=0 4x+y-5z+8w=0 5x-7y+2z-w=0​

Answers

Answered by rashich1219
13

Given:

x+y-2z+3w=0,

x-2y+z-w=0,

4x+y-5z+8w=0 and

5x-7y+2z-w=0

To Find:

Solve given equation.

Solution:

Lets , take 2nd equation,x-2y+z-w=0

solve it for z;

z=w+2y-x

Now , we can replace z in the other equations to get,

x+y-2(w+2y-x)+3w=0,\\4x+y-5(w+2y-x)+8w=0,\\5x-7y+2(w+2y-x)-w=0

On solving we get,

3x-3y+w=0,\\9x-9y+3w=0,\\3x-3y+w=0

Here, we getting all three equations same.

Answered by palepugurubramhachar
0

solve the equation x+y-2z+3w=0

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