Solve x+y=5 And 2x-3y=4 using elimination method
Answers
Answered by
564
x + y = 5 ( equation 1 )
2x - 3y = 4 ( equation 2 )
Now,
multiplying (eq.1) by 2 and subtracting (eq.2) from ( eq.1 )
(2x + 2y = 10) - (2x - 3y = 4 )
=> 2x + 2y - 2x + 3y = 6
=> 5y = 6
=> y = 6/5
Putting the value of y in ( eq.1 )
=> x+ y = 5
=> x + 6/5 = 5
=> x = 5 - 6/5
=> x = 19/5
2x - 3y = 4 ( equation 2 )
Now,
multiplying (eq.1) by 2 and subtracting (eq.2) from ( eq.1 )
(2x + 2y = 10) - (2x - 3y = 4 )
=> 2x + 2y - 2x + 3y = 6
=> 5y = 6
=> y = 6/5
Putting the value of y in ( eq.1 )
=> x+ y = 5
=> x + 6/5 = 5
=> x = 5 - 6/5
=> x = 19/5
Answered by
213
Here is your answer
we have,
x + y = 5. ----->1
2x - 3y = 4. ----->2
by elimination,
2x + 2y = 10
2x. -. 3y =4
__________
-5y = -6
y = 6/5. -------->3
putting eq. no 3 into 1, we get ,
x + y = 5
x + 6/5 = 5
after solving ,
5x + 6 = 25
5x = 19
x = 19/5 -------->4
x = 19/4
y = 6/5
hope it will help you..
we have,
x + y = 5. ----->1
2x - 3y = 4. ----->2
by elimination,
2x + 2y = 10
2x. -. 3y =4
__________
-5y = -6
y = 6/5. -------->3
putting eq. no 3 into 1, we get ,
x + y = 5
x + 6/5 = 5
after solving ,
5x + 6 = 25
5x = 19
x = 19/5 -------->4
x = 19/4
y = 6/5
hope it will help you..
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