Solve x+y=7 and 3x-2y=11 by substitution method and hence find the value of 'm' for which y = mx-3
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it is a similar problem of this question because only value is not similar but the type of question is same
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Step-by-step explanation:
x+y = 7 - (1)
3x - 2y = 11 - (2)
we multiplying eq (1) by 2 and eq (2) by 1
2x + 2y =14 - (3)
3x - 2y = 11 - (4)
adding eq 3 and 4 we get
(2x + 2y)+ ( 3x - 2y) = 14 + 11
2x + 2y + 3x - 2y = 25
5x = 25
x = 25 ÷ 5
x = 5
Now putting the value of x in eq (1)
x +y =7
5 + y = 7
y = 7 - 5
y = 2
Now putting the value in y = mx-3
y = mx-3
2 = m 5 - 3
2 = m 2
2÷2 =m
m = 1
Hope it help you
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