Math, asked by aryangowda125, 9 days ago

Solve x+y=8 and 2x-y=1 by
substitutional method​

Answers

Answered by BrainlyAnnabelle
1

Step-by-step explanation:

\sf\underline\red{Given~:-}

  • x + y = 8 → ①
  • 2x - y = 1 → ②

\sf\red{From~eqn~①~} ,

  • x + y = 8
  • x = 8 - y → Eqn 1

Now ,

\sf\red{ Substitute~x~value~in~eqn~2}

  • 2x - y = 1
  • 2 ( 8 - y ) - y = 1
  • 16 - 2y - y = 1
  • 16 - 3y = 1
  • - 3y = 1 - 16
  • - 3y = - 15

\green{arrow} Cancel {~-~} on both sides

  • 3y = 15
  • y = \frac{15}{3}
  • y = 5

\sf\red{Put~y~value~in~eqn~1~}

  • x = 8 - y
  • x = 8 - 5
  • x = 3

:. x = 3 and y = 5

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