solve X + Y = 83 and 4 x + Y = 182 by elimination method, Letv, class 10th ,maths
Answers
Step-by-step explanation:
x+y = 83 --------(1)
4x+y = 182 ---------(2)
multiply eq (1) with 4
now eq (1) is 4x + 4y =332
subtracting eq (2) from eq(1)
i.e,
4x+4y = 332
4x + y = 182
so that x gets cancelled and then
3y = 150
y = 50
substitution of y value in any of these equations gives x
value also
4x + 50 = 182
4x = 132
x = 33
Given : X + Y = 83 and 4 x + Y = 182
To find : value of x & y by elimination method
Solution:
x + y = 83 Eq1
4x + y = 182 Eq 2
Eq2 - Eq1 will eliminate y
=> 4x - x = 182 - 83
=> 3x = 99
Dividing both sides by 3
=> x = 33
4 * eq1 - Eq2 will eliminate x
=> 4y - y = 332 - 182
=> 3y = 150
=> y 50
x = 33 & y = 50
Learn more:
x/3+5y=13; 2x+y/2=19 Solve the given simultaneous equation ...
https://brainly.in/question/4564843
Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in
https://brainly.in/question/8168066
1) Solve the equations 11x + 6y - 4330; 22x + 5y = 7330 andfind the ...
https://brainly.in/question/13194026