Question

Solve x, y of Az
me y of P = (22") 6-63).
(810)
and QA1B​

Answer 1

$2A+B=\left[\begin{array}{ccc}9&1\\0&10\end{array}\right] \\\\\\2\left[\begin{array}{ccc}2&3\\x&4\end{array}\right] + \left[\begin{array}{ccc}5&y\\4&2\end{array}\right]=\left[\begin{array}{ccc}9&1\\0&10\end{array}\right] \\\\\\\left[\begin{array}{ccc}4&6\\2x&8\end{array}\right] + \left[\begin{array}{ccc}5&y\\4&2\end{array}\right]=\left[\begin{array}{ccc}9&1\\0&10\end{array}\right]$

$\left[\begin{array}{ccc}4+5&6+y\\2x+4&8+2\end{array}\right] =\left[\begin{array}{ccc}9&1\\0&10\end{array}\right] \\\\\\\left[\begin{array}{ccc}9&6+y\\2x+4&10\end{array}\right] =\left[\begin{array}{ccc}9&1\\0&10\end{array}\right]\\\\\\Equating\:\:both \:\:matrices,\:\:we\:\:get\\\\2x+4=0\\=>\:\:\:2x=-4\\=>\:\:\:x=\frac{-4}{2} \\=>\:\:\:x = -2\\\\AND\\\\6+y=1\\=>\:\:\:y=1-6\\=>\:\:\:y=-5$