solve ( x y + y z) ² - 2x y²z
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(xy + yz)2 - 2x2y2z when x = - 1,y = 1,z = 2 [y(x + z)]2 - 2x2y2z y2[x2 + z2 + 2xz - 2x2z] (1)2[( - 1)2 + 22 + 2( - 1)(2) - 2( - 1)2(2)] [1 + 4 - 4 - 4] ...
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x²y²+y²z²
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(xy + yz) ²-2xy²z
(a+b)²
x²y²+y²z²+2xy²z-2xy²z
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