Question

solve : x + y + z + 1 =0

x+2y + 3z +4 = 0

x +3y + 4z +6 = 0​

Answer 1

Answer:

x = 1

y = -1

z = -1

Step-by-step explanation:

x + y + z + 1 =0  -------------- equation 1

x+2y + 3z +4 = 0  ------------ equation 2

x +3y + 4z +6 = 0​ ------------equation 3

------------

LHS equation 1 = LHS equation 2 as RHS for both is 0

x + y + z + 1 = x+2y + 3z +4

y + 2z + 3 = 0 ......................... equation 4

----------------------------

LHS equation 1 = LHS equation 3 as RHS for both is 0

x + y + z + 1 = x +3y + 4z +6

2y + 3z + 5 = 0

y + 3z/2 + 5/2 = 0 ............................... equation 5

--------------------------------------

LHS equation 4 = LHS equation 5 as RHS for both is 0

y + 2z + 3 = y + 3z/2 + 5/2

2z + 3 = 3z/2 + 5/2

4z + 6 = 3z + 5

z = -1

-------------------------

Put value of z in equation 4

y + 2z + 3 = 0

y -2 + 3 = 0

y = -1

-------------------------

Put value of z and y in equation 1

x + y + z + 1 =0

x -1 -1 + 1 = 0

x = 1